3v4l.org

run code in 300+ PHP versions simultaneously
<?php $num = [2.117647058, 0.002117647058]; foreach($num as $n){ if(substr($n,0,1) > 0){ echo round($n, 2) . "\n"; }else{ preg_match("/([0\.]+)(\d{1,2})/", $n, $m); echo $m[0] . "\n"; } }

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27.75 ms | 406 KiB | 5 Q