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<?php $PopulationOfTexas = array( 1999 => 20.56, // in millions 2000 => 21.56, 2001 => 22.56, 2002 => 23.56 ); //generate an array sohwing the difference in each year compared to the previous year $differneces = array(); $lastmonth = null; foreach($PopulationOfTexas as $k=>$v){ if(empty($lastmonth)){$lastmonth = $k; continue;} $differneces[$k] = $k - $lastmonth; $lastmonth = $k; //use this later $lastitem = array("year"=>$k, "data"=>$v); } //print_r($differneces); //get the average difference per year $count = 0; $total = 0; foreach($differneces as $k=>$v){ $count++; $total += $v; } $average = number_format(($total/$count), 2); //print_r($average); //make a prediction print_r($lastitem);
Output for 4.3.0 - 4.3.11, 4.4.0 - 4.4.9, 5.0.0 - 5.0.5, 5.1.0 - 5.1.6, 5.2.0 - 5.2.17, 5.3.0 - 5.3.29, 5.4.0 - 5.4.45, 5.5.24 - 5.5.35, 5.6.7 - 5.6.28, 7.0.0 - 7.0.20, 7.1.0 - 7.1.25, 7.2.0 - 7.2.33, 7.3.0 - 7.3.33, 7.4.0 - 7.4.33, 8.0.0 - 8.0.30, 8.1.0 - 8.1.28, 8.2.0 - 8.2.18, 8.3.0 - 8.3.6
Array ( [year] => 2002 [data] => 23.56 )

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