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<?php $str = 'I only want the first 60 words of $output that has been uploaded 100 words to the database to be shown on my page, what is the simplest way for me to do this? I want $output[]="description to only fetch first 60 words from the database. ** I have tried a lot method but isnt working for me** I only want the first 60 words of $output that has been uploaded 100 words to the database to be shown on my page, what is the simplest way for me to do this? I want $output[]="description to only fetch first 60 words from the database. ** I have tried a lot method but isnt working for me**'; echo count(explode(" ", $str)) . " words in string\n\n"; echo "first 60 is:\n" . implode(" ", array_slice(explode(" ", $str), 0, 60));
Output for 7.1.25 - 7.1.33, 7.2.0 - 7.2.33, 7.3.0 - 7.3.33, 7.4.0 - 7.4.33, 8.0.0 - 8.0.30, 8.1.0 - 8.1.28, 8.2.0 - 8.2.19, 8.3.0 - 8.3.4, 8.3.6 - 8.3.7
113 words in string first 60 is: I only want the first 60 words of $output that has been uploaded 100 words to the database to be shown on my page, what is the simplest way for me to do this? I want $output[]="description to only fetch first 60 words from the database. ** I have tried a lot method but isnt working for me** I only want the
Output for 8.3.5
Warning: PHP Startup: Unable to load dynamic library 'sodium.so' (tried: /usr/lib/php/8.3.5/modules/sodium.so (libsodium.so.23: cannot open shared object file: No such file or directory), /usr/lib/php/8.3.5/modules/sodium.so.so (/usr/lib/php/8.3.5/modules/sodium.so.so: cannot open shared object file: No such file or directory)) in Unknown on line 0 113 words in string first 60 is: I only want the first 60 words of $output that has been uploaded 100 words to the database to be shown on my page, what is the simplest way for me to do this? I want $output[]="description to only fetch first 60 words from the database. ** I have tried a lot method but isnt working for me** I only want the
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117.9 ms | 402 KiB | 186 Q