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<?php $prevYear = date("Y", strtotime("-1 year", strtotime(new \DateTime())); $nextYear = date("Y", strtotime("2013 +1 year")); var_dump($prevYear);
Output for 5.3.0 - 5.3.28, 5.4.0 - 5.4.25
Parse error: syntax error, unexpected ';' in /in/1jeEA on line 2
Process exited with code 255.
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201.6 ms | 1399 KiB | 62 Q