3v4l.org

run code in 300+ PHP versions simultaneously
<?PHP $inicio=10; $final=50; do{ if (($inicio % 2)==0) echo("El nĂºmero $inicio es pa r.<BR>"); $inicio++; }while ($inicio<=$final); ?
Output for 5.3.0 - 5.3.28, 5.4.0 - 5.4.28
Parse error: syntax error, unexpected '?' in /in/rb3k9 on line 9
Process exited with code 255.

preferences:
192.12 ms | 1395 KiB | 65 Q