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@ 2014-03-09T04:49:57Z

<?php
$date = '2014-03-04';
$yearDay = date("z", strtotime($date)) + 1;
$yearDays = date("z", strtotime(date("Y", strtotime($date))."-12-31"));
echo $yearDays.' '.$yearDay.' ';

echo $yearDay/$yearDays;
?>

Output
Performance
VLD
References
Branches

date: documentation ( source)
strtotime: documentation ( source)

preferences:dark modelive preview

39.05 ms | 402 KiB | 5 Q